LeetCode 42 接雨水图解草图.excalidraw


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Excalidraw Data

Text Elements

一开始0, 右侧的水是平面的高度为0 ^bHR4jyVR

1加入后, 右侧的水是高度为1, 长度无穷的 ^yoNxE5sX

0加入, 因为0起不到挡板的作用 ^shqx0Icb

2加入, 挡住了右边, 因此左侧的水可以被计算, 而右侧的水高是2 ^UeV9fNj1

观察下来: 我们可以维护一个栈, 栈顶元素是当前右侧的水上高(水面的高度), 如果新元素进来后发现比水高,这会导致中间的水可以被计算, 而为了计算这个 面积, 我们需要知道上一个水高的位置(也就是当期的水高是谁导致的)和底的高度, 而且有大小关系, 这就是单调栈 ^i7ZLsFTR

1,加入, 入不到作用, ^zfBTHEcd

假设来了个2 ^DzE6joPU

什么时候计算接到的水: 发现当前值大于栈顶时 ^FhIScfDb

Embedded Files

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